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5x+4x^2=450
We move all terms to the left:
5x+4x^2-(450)=0
a = 4; b = 5; c = -450;
Δ = b2-4ac
Δ = 52-4·4·(-450)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-85}{2*4}=\frac{-90}{8} =-11+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+85}{2*4}=\frac{80}{8} =10 $
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